Probability of an outcome = P
Number of trials of an event = n
Number of occurrences of an outcome = r
where 
Use the
button on your calculator
(pronounced n choose r)
Assume independence X~B(n,p)
a) A
sample of parent population must be random
b) A
sample must be large enough to be representative
c) Simple
random sample every population member has an equal chance of being chosen
d) A
population made of sub groups (e.g. sex, age) needs a stratified sample. The number chosen from each stratum is
proportional to the size of the stratum.
See sheet previously provided
Expected average ![]()
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Variance = Var(x) or V(x)



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X~N(μ,σ²)
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Total area = 1
z is the standardised value of observation X
Φ(z) = P(z ≤ Z)
P(z ≤ 1.3) = Φ(1.3)
P(z ≤ 1.3) = 1-Φ(1.3)
P(z ≤ -1.3) = 1-Φ(1.3)
P(z ≤ -1.3) = 1-[1-Φ(1.3)] = Φ(1.3)
When p=½ and any n or for large values of n (n>25).
X~B(n,p) → Y~N(np, np(1-p)) where np=μ and np(1-p)=σ²
Discrete → Continuous
●Remember.
Discrete
(Binomial) Continuous
(
P(x > 50) → P(Y > 50.5)
P(x < 50) → P(Y > 49.5)
P(30 < x < 60) → P(30.5 < Y < 59.5)
P(30 ≤ x ≤ 60) → P(29.5 < Y < 60.5)
sample mean
Distribution
of sample mean is like a normal distribution.
For sample size n, mean is μ, variance is σ²/n i.e. 
Standard deviation of
i.e.
is standard error.
Central limit theorem
● the distribution of sample means are approx. normal if sample size is > 30
● the
variance is ![]()
When we dont know μ & σ² of parent population, we make estimates using our sample.
- sample mean
(unbiased)
is an unbiased
estimator of σ² (s² is sample
variance)
The likelihood that the population mean (μ) lies within a
given interval.
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90%
μ ± 1.645 s.e.
95% μ ± 1.96 s.e.
99% μ ± 2.575 s.e.
68% μ ± 1 s.e.
Remember parent population σ is unknown so simply
multiply by ![]()